>> set [foo bar baz] copy [] >> E> You will find that only foo is set set to a block, whereas bar and baz E> are initialized to the value none. This is unlike using E> set [foo bar baz[] 3 ;- (i.e. some non-series value E> where all words will be initialized to the same value.
Excellent point Elan! And a great example of how what we *think* is just a different idiom might actually behave differently. -- Gregg -- To unsubscribe from this list, just send an email to [EMAIL PROTECTED] with unsubscribe as the subject.
