[EMAIL PROTECTED] wrote:
>I'm trying to get a pidof a php script by capturing the path: like /home/somebody/my_script which will be the first arg. to the bash scriptCould anybody tell me what's wrong with this script ? I'm new to scripting in general so any help would be apreciated ! #!/bin/bash 1st_arg=$1 prosesses=`lsof -i` prosessid=`echo $prosesses | gawk /1st_arg/'{print $2}'`
In your awk stmt you search for '1st_arg' rather than the value of the variable 1st_arg, which would be $1st_arg - or perhaps ${1st_arg}, as $1 is something else...
echo $prosessid
if [ -z "$prosessid" ]
echo "not running"
fi
exit 0
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