>Jon Haugsand wrote:
>> * [EMAIL PROTECTED]
>>
>>>#!/bin/bash
>>>1st_arg=$1
>>
>> number not allowed in front.
>>
>>
>>>prosesses=`lsof -i`
>>>prosessid=`echo $prosesses | gawk /1st_arg/'{print $2}'`
>>
>> Cannot understand this to work in gawk. In any case, you might do
>> this a lot more effective:
>>
>>
>>>echo $prosessid
>>>if [ -z "$prosessid" ]
>>
>> missing "then"
>>
>>
>>>echo "not running"
>>>fi
>>
>>
>>
>>>exit 0
>>
>> Not necessary
>>
>>
>> My suggestion:
>>
>> #!/bin/bash
>> process=`lsof -i | grep $1 | gawk '{print $2 }'`
>> if [ "$process" = "" ]; then
>> echo "not running"
>> else
>> echo $process
>> fi
>>
>Another point is: if you want the PID of the currently processing shell
>(ie. the one that interprets your script), then according to man bash
>you can just use the special variable $, like in '$$'.
>
>/jan
Thanks Jan just learned a bunch !
Guess I'll go and RTFM :)
RGDS
Lars
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