isn't it: x[ft]=234/F[MHz] Then: x[ft]*Vf?
NOT 2 fourty-six/F[MHz] --- Steve <[EMAIL PROTECTED]> wrote: > > I'm thinking about building this: > > http://www.repeater-builder.com/rbtip/exposeddipole.html > > However, I'm having trouble reproducing the > calculation that yields a > 63.8 inch coax length. I'm assuming the velocity > factor is .67 and > keep getting 68 inches for a 5/4 wave...off from > 63.8 inches as in > the article. I can reproduce the 40.8 inch > dimension (3/4 wave) > within a fraction of an inch.... > > I'm using L = 246/F*Vf for a quarter wavelength > (about 13.5 inches). > > What am I missing? I'd like to understand where the > numbers come > from before I start cutting aluminum and coax.... > > Steve, KE4MOB > > > > > > > Yahoo! Groups Links > > > [EMAIL PROTECTED] > > > > > > __________________________________ Do you Yahoo!? Yahoo! Mail is new and improved - Check it out! http://promotions.yahoo.com/new_mail Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/Repeater-Builder/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
