Yes it does, if you have an isolator installed at the transmitter. With an
isolator on the transmitter the transmitter will always see 50 ohms no
matter what the load on the other end of the isolator is. There should be no
problems with off frequency reactance when an isolator is used. But any
reflected power into the isolators load (from on frequency signal) is lost
in heat and never reaches the antenna.

 

With an isolator, if the duplexer is not presenting a pure 50 ohms (at the
wanted frequency) to the output of the isolator you could put a wattmeter
between the isolator and the isolator load and change cable lengths between
duplexer and isolator or tune a Z matcher if you have one, for minimum power
into the isolators load. That will give you maximum power to the antenna and
you will have a near perfect 50 ohm load on the transmitter always.

 

73

Gary  K4FMX

 

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From: [email protected]
[mailto:[EMAIL PROTECTED] On Behalf Of [EMAIL PROTECTED]
Sent: Sunday, July 01, 2007 8:30 PM
To: [email protected]
Subject: Re: [Repeater-Builder] Cable formula

 

Doesn't the isolator typically installed at the transmitter output  spin off
any anything reflected from the duplexer (or the feedline) into it's load? 

 

 

In a message dated 7/1/2007 5:33:33 P.M. Pacific Daylight Time,
[EMAIL PROTECTED] writes:

But at some off frequency that is not 50+j0
that impedance is going to get transformed into something yet again by the
time the cable reaches the transmitter.

 





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See what's free at AOL.com <http://www.aol.com?ncid=AOLAOF00020000000503> . 

 

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