Actually, the original poster DOES want to drive an LED.

 

Chris

Kb0wlf

 

From: [email protected]
[mailto:[email protected]] On Behalf Of Rick Szajkowski
Sent: Friday, September 25, 2009 10:47 AM
To: [email protected]
Subject: Re: [Repeater-Builder] Busy Signal (COS) inverter Circuit.

 



thats fine to drive a LED .. but he has an LED and want to use that 'signal'
to drive an input on a controller 

Rick
va3rzs

On Fri, Sep 25, 2009 at 11:18 AM, Jim Brown <[email protected]> wrote:

  

[Attachment(s) from Jim Brown included below] 


Here is the circuit I would recommend to light an LED when the signal input
is at or near ground and will extinguish the LED when the input is at or
near + 5 VDC.  It would provide minimal loading on a microprocessor output
signal.

73 - Jim  W5ZIT

--- On Fri, 9/25/09, tait700 <[email protected]> wrote:


From: tait700 <[email protected]>
Subject: [Repeater-Builder] Busy Signal (COS) inverter Circuit.
To: [email protected]
Date: Friday, September 25, 2009, 6:33 AM

  

Hello,
Was wondering if someone knowledgeable would be able to advise me on the
best way to proceed with this,
I need to extract a signal to power a normal LED that indicates when the
Mute has opened on a Receiver.
The Receiver has a "Busy" line coming from the Micro that supplies 5V DC
when the mute is closed ( Quiet ) and goes to OV when the Audio is open (
Audible )
I don't have any further info on the current available from the micro and am
a little dubious about running a small SPDT relay off this signal.
I searched the RB site and found the article concerning the "maxtrac cor
buffer" which uses a Transistor to invert the logic but am not sure how to
apply this to a LED ( 20ma ) and whether the resistor on the Base input
would be the right value.
If i could do this without risking the health of the micro ( which controls
everything on the Board ) i would be very happy.

Any info would be most appreciated,

Regards,


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