Thank you very much, Jim.
Exactly what i was looking for.

Thanks again,

Regards.

--- In [email protected], Jim Brown <w5...@...> wrote:
>
> Here is the circuit I would recommend to light an LED when the signal input 
> is at or near ground and will extinguish the LED when the input is at or near 
> + 5 VDC.  It would provide minimal loading on a microprocessor output signal.
> 
> 73 - Jim  W5ZIT
> 
> --- On Fri, 9/25/09, tait700 <cscan...@...> wrote:
> 
> From: tait700 <cscan...@...>
> Subject: [Repeater-Builder] Busy Signal  (COS) inverter Circuit.
> To: [email protected]
> Date: Friday, September 25, 2009, 6:33 AM
> 
> 
> 
> 
> 
> 
>  
> 
> 
> 
> 
>     
>                   Hello,
> 
> Was wondering if someone knowledgeable would be able to advise me on the best 
> way to proceed with this,
> 
> I need to extract a signal to power a normal LED that indicates when the Mute 
> has opened on a Receiver.
> 
> The Receiver has a "Busy" line coming from the Micro that supplies 5V DC when 
> the mute is closed ( Quiet ) and goes to OV when the Audio is open ( Audible )
> 
> I don't have any further info on the current available from the micro and am 
> a little dubious about running a small SPDT relay off this signal.
> 
> I searched the RB site and found the article concerning the "maxtrac cor 
> buffer" which uses a Transistor to invert the logic but am not sure how to 
> apply this to a LED ( 20ma ) and whether the resistor on the Base input would 
> be the right value.
> 
> If i could do this without risking the health of the micro ( which controls 
> everything on the Board ) i would be very happy.
> 
> 
> 
> Any info would be most appreciated,
> 
> 
> 
> Regards,
> 
> 
> 
> 
>  
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> 
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