I adjusted the loop positions, trying to maintain symmetry of the curve, aiming for 1 db on the analyzer. I didn't adjust the loops while looking at the RL. How would I translate RL into IL?
On Tue, Apr 20, 2010 at 6:02 PM, Jeff DePolo <j...@broadsci.com> wrote: > > > > What process did you go through when setting the insertion loss to the 1 dB > you were targetting? Did you optimize the coupling angle of the loops for > maximum return loss at (or near) the desired 1 dB of insertion loss? > > --- Jeff WN3A > > > > -----Original Message----- > > From: Repeater-Builder@yahoogroups.com<Repeater-Builder%40yahoogroups.com> > > [mailto:Repeater-Builder@yahoogroups.com<Repeater-Builder%40yahoogroups.com>] > On Behalf Of Larry Horlick > > Sent: Tuesday, April 20, 2010 5:54 PM > > To: Repeater-Builder@yahoogroups.com<Repeater-Builder%40yahoogroups.com> > > Subject: Re: [Repeater-Builder] Sinclair C-Series cable lengths > > > > > > > > >>But were the loops adjusted to maximize return loss at the desired > > >>inseretion loss setting? That's the key point. Or did you > > just "dial in" 1 > > >>dB of insertion loss and call it good? > > > > > > Not sure what u mean?? > > > > > > > > > > > > > > > > > > No virus found in this incoming message. > > Checked by AVG - www.avg.com > > Version: 9.0.801 / Virus Database: 271.1.1/2792 - Release > > Date: 04/20/10 02:31:00 > > > > > > > > >
