Github user srowen commented on a diff in the pull request:
https://github.com/apache/spark/pull/10208#discussion_r47208027
--- Diff: core/src/main/scala/org/apache/spark/util/Utils.scala ---
@@ -331,6 +331,30 @@ private[spark] object Utils extends Logging {
}
/**
+ * A file name may contain some invalid url characters, such as " ".
This method will convert the
+ * file name to a raw path accepted by `java.net.URI(String)`.
+ *
+ * Note: the file name must not contain "/" or "\"
+ */
+ def encodeFileNameToURIRawPath(fileName: String): String = {
--- End diff --
Yes, it must be `file:/abc:xyz` since you need to tell it it needs to be
treated as a file name. Meh, at this point why not just `new URI("file:/" +
fileName).getRawPath.substring(1)` and keep it simple?
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