Github user zasdfgbnm commented on a diff in the pull request:
https://github.com/apache/spark/pull/14231#discussion_r72167136
--- Diff: bin/spark-class ---
@@ -65,24 +65,25 @@ fi
# characters that would be otherwise interpreted by the shell. Read that
in a while loop, populating
# an array that will be used to exec the final command.
#
-# The exit code of the launcher is appended to the output, so the parent
shell removes it from the
-# command array and checks the value to see if the launcher succeeded.
-build_command() {
- "$RUNNER" -Xmx128m -cp "$LAUNCH_CLASSPATH"
org.apache.spark.launcher.Main "$@"
- printf "%d\0" $?
-}
+# To keep both the output and the exit code of the launcher, the output is
first converted to a hex
+# dump which prevents the bash from getting rid of the NULL character, and
the exit code retrieved
+# from the bash array ${PIPESTATUS[@]}.
+#
+# Note that the seperator NULL character can not be replace with space or
'\n' so that the command
+# won't fail if some path of the user contain special characher such as
'\n' or space
+#
+# Also note that when the launcher fails, it might not output something
ending with '\0' [SPARK-16586]
+_CMD=$("$RUNNER" -Xmx128m -cp "$LAUNCH_CLASSPATH"
org.apache.spark.launcher.Main "$@"|xxd -p|tr -d '\n';exit ${PIPESTATUS[0]})
--- End diff --
The biggest problem to achieve this is: If success, the exit status of the
process will be 0 and the output of the process will be something sperate by
'\0'. Bash don't allow us to store '\0' in a bash variable, we should find some
alternative way to store it, which makes $? no longer the exit status of the
launcher..
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