Github user viirya commented on the issue:
    > Why equi-join is free from the issues?
    Assume the equi-join predicates are in the form like `t1.a = rand(t2.b) && 
t1.c = rand(t2.d)`. When we compare the equi-join keys `(t1.a, t1.c)` and 
`(rand(t2.b), rand(t2.d))`, we compare them all and won't skip `t1.c = 
rand(t2.d)` if `t1.a = rand(t2.b)` is false. That says we can pull out it to 
downstream project and don't need to worry changing the number of calls.

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