maropu commented on a change in pull request #25001: [SPARK-28083][SQL] Support
LIKE ... ESCAPE syntax
URL: https://github.com/apache/spark/pull/25001#discussion_r303877847
##########
File path:
sql/catalyst/src/main/scala/org/apache/spark/sql/catalyst/expressions/regexpExpressions.scala
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@@ -83,33 +83,39 @@ abstract class StringRegexExpression extends
BinaryExpression
% matches zero or more characters in the input (similar to .* in
posix regular
expressions)
- The escape character is '\'. If an escape character precedes a
special symbol or another
- escape character, the following character is matched literally. It
is invalid to escape
- any other character.
-
Since Spark 2.0, string literals are unescaped in our SQL parser.
For example, in order
to match "\abc", the pattern should be "\\abc".
When SQL config 'spark.sql.parser.escapedStringLiterals' is enabled,
it fallbacks
to Spark 1.6 behavior regarding string literal parsing. For example,
if the config is
enabled, the pattern to match "\abc" should be "\abc".
+ * escape - a optional string. The default escape character is the '\'
but a different one
+ can be selected by using the ESCAPE clause. If an escape character
precedes a special
+ symbol or another escape character, the following character is
matched literally. It is
+ invalid to escape any other character.
Review comment:
How about this?
```
* escape - an optional string. The default escape character is the '\'
. If an escape character
precedes a special symbol or another escape character, the
following character is matched
literally. It is invalid to escape any other character.
```
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