ulysses-you commented on issue #26860: [SPARK-30230][SQL] Like ESCAPE syntax can not use '_' and '%' URL: https://github.com/apache/spark/pull/26860#issuecomment-565341754 If '%' and '_' as escape, how to use the real pattern. Like this ? ``` SELECT 'abcd' LIKE 'ab%%' escape '%'; ``` But actually `StringUtils.escapeLikeRegex` will do this check. ``` while (in.hasNext) { in.next match { case c1 if c1 == escapeChar && in.hasNext => val c = in.next c match { case '_' | '%' => out ++= Pattern.quote(Character.toString(c)) case c if c == escapeChar => out ++= Pattern.quote(Character.toString(c)) case _ => fail(s"the escape character is not allowed to precede '$c'") } case c if c == escapeChar => fail("it is not allowed to end with the escape character") // we will never run these code path case '_' => out ++= "." case '%' => out ++= ".*" case c => out ++= Pattern.quote(Character.toString(c)) } } ```
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