Mathematically, we know that the Fourier transform (FT) is a linear
operator, so FT{f1+f2}=FT{f1} +FT{f2}. No mangled convolution.
Nick
Brian H. Toby wrote:
> I had to think for a bit: the Fourier transform of a sum is equal to
> the sum of the terms transformed individually, so the G(r) for a
> mixture is the weighted sum of G(r) for the components.
>
> Brian
>
> On Sep 27, 2006, at 9:05 AM, Andy Fitch wrote:
>
>> We have a question about pdf analysis. If my sample is two
>> phase, so the diffraction pattern is the sum of two individual
>> patterns, what does the G(r) show? Is it just the sum of two
>> individual G(r)s or some mangled convolution between the two?
>
>
--
Dr Nicholas Armstrong
NIST-UTS Research Fellow
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