2009-10-12 22:18, Tero Tilus:
> Expression x!=y is instead just syntactic sugar for !(x==y).
To illustrate how this affects #should, think of
'some string'.should != 'some string'
Now Ruby internals kick in and desugar this (before anything is even
executed) to
!('some string'.should == 'some string')
Which obviously does not fail.
--
Tero Tilus ## 050 3635 235 ## http://tero.tilus.net/
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