Hello! I believe a 0mq socket will never block, thus it's okay to keep a direct queue in front of an omzmq3 action. Is it accurate ?
I plan to use a 0mq PUB socket like this : action(Type="omzmq3" SockType="PUB" Action="BIND" Description="tcp://*:11515" SndHWM="1000") According to 0mq documentation (http://api.zeromq.org/2-1:zmq-socket) : "When a *ZMQ_PUB* socket enters an exceptional state due to having reached the high water mark for a *subscriber*, then any messages that would be sent to the *subscriber* in question shall instead be dropped until the exceptional state ends. The *zmq_send()* function shall never block for this socket type." So, could rsyslog be blocked if something goes "wrong" with the PUB socket? How? Thanks! Philippe Muller _______________________________________________ rsyslog mailing list http://lists.adiscon.net/mailman/listinfo/rsyslog http://www.rsyslog.com/professional-services/ What's up with rsyslog? Follow https://twitter.com/rgerhards NOTE WELL: This is a PUBLIC mailing list, posts are ARCHIVED by a myriad of sites beyond our control. PLEASE UNSUBSCRIBE and DO NOT POST if you DON'T LIKE THAT.
