Hopefully Brian will jump on this question, as this is not an "official Adiscon module". In this case, I even really have no clue at all ;)
Rainer On Tue, 2013-04-23 at 18:06 +0200, Philippe Muller wrote: > Hello! > > I believe a 0mq socket will never block, thus it's okay to keep a direct > queue in front of an omzmq3 action. > Is it accurate ? > > I plan to use a 0mq PUB socket like this : > > action(Type="omzmq3" SockType="PUB" Action="BIND" > Description="tcp://*:11515" SndHWM="1000") > > According to 0mq documentation (http://api.zeromq.org/2-1:zmq-socket) : > "When a *ZMQ_PUB* socket enters an exceptional state due to having reached > the high water mark for a *subscriber*, then any messages that would be > sent to the *subscriber* in question shall instead be dropped until the > exceptional state ends. The *zmq_send()* function shall never block for > this socket type." > > So, could rsyslog be blocked if something goes "wrong" with the PUB socket? > How? > > Thanks! > > > Philippe Muller > _______________________________________________ > rsyslog mailing list > http://lists.adiscon.net/mailman/listinfo/rsyslog > http://www.rsyslog.com/professional-services/ > What's up with rsyslog? Follow https://twitter.com/rgerhards > NOTE WELL: This is a PUBLIC mailing list, posts are ARCHIVED by a myriad of > sites beyond our control. PLEASE UNSUBSCRIBE and DO NOT POST if you DON'T > LIKE THAT. _______________________________________________ rsyslog mailing list http://lists.adiscon.net/mailman/listinfo/rsyslog http://www.rsyslog.com/professional-services/ What's up with rsyslog? Follow https://twitter.com/rgerhards NOTE WELL: This is a PUBLIC mailing list, posts are ARCHIVED by a myriad of sites beyond our control. PLEASE UNSUBSCRIBE and DO NOT POST if you DON'T LIKE THAT.
