Hi! On Aug 19, 3:53 pm, rjf <[email protected]> wrote: > Consider > integrate(f(x,y),x*y). > > do you compute d(x*y) as x*dy+y*dx and compute integrate(f(x) > *x,y) + integrate(f(x)*y,x)? > > Here's another interpretation of variable = x^2... > > integrate(f(x),x^2) = integrate(integrate(f(x),x),x). > that is, an iterated integral. This is like > > (d ^2 f(x))/dx^2 notation for derivatives, where the derivative is > definitely NOT with respect to x^2.
But would you agree that my suggestion f.integral(x[,g]) --- f function, x variable, g function (optional, default g(x)=x) makes sense, which should return the integral (f * dg/dx) dx ? I think that has no ambiguity in it (even if f or g depends on further variables), and it would just mean to extend Sage's .integral() method so that Maxima is used in a more clever way. Cheers, Simon --~--~---------~--~----~------------~-------~--~----~ To post to this group, send an email to [email protected] To unsubscribe from this group, send an email to [email protected] For more options, visit this group at http://groups.google.com/group/sage-devel URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
