On 2/4/12 11:24 AM, Keshav Kini wrote:
On Saturday, February 4, 2012 11:43:44 PM UTC+8, Andrey Novoseltsev wrote:But in definite integrals the variable of integration is a dummy one and does not exist out of the integral! +1. This behavior makes no sense to me.
So what happens in a case like this? sage: f(x,y,z)=sin(x*y*z) sage: integrate(f,(y,0,3)) Does the result become a function (x,z) |--> whatever? I can see it making sense, but I can also see it causing problems. Thanks, Jason -- To post to this group, send an email to sage-devel@googlegroups.com To unsubscribe from this group, send an email to sage-devel+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URL: http://www.sagemath.org
