David Kirkby <[email protected]> writes: > On 23 July 2012 16:40, tvn <[email protected]> wrote: >> >> That's what I mean: my Debian OS is *NOT* 64 bit -- uname -a *DOES NOT* >> tell you about the OS but rather the capability of the machine hardware. > > > I don't know how uname is implemented in Linux, but according to > POSIX, the -m option gives the hardware. The -a option specifies > several options, including the -m. So it should give the hardware, and > not the software
A breakdown of the uname output: Linux wooly 2.6.32-5-amd64 #1 SMP Sun May 6 05:12:07 UTC 2012 x86_64 GNU/Linux -s -n -r -v -m -o I think what we're mostly talking about is the -r output, not the -m output. The -r output indicates the kernel was built for the amd64 architecture and is thus a 64-bit kernel. This is of course Linux-specific, since the Linux kernel build process determines the string "2.6.32-5-amd64" which is then embedded in the built kernel. -Keshav ---- Join us in #sagemath on irc.freenode.net ! -- -- To post to this group, send an email to [email protected] To unsubscribe from this group, send an email to [email protected] For more options, visit this group at http://groups.google.com/group/sage-devel URL: http://www.sagemath.org
