> I would advocate that RLF is a very good approximation of what should > be RR. Perhaps one good direction to take is to try to make RLF > smarter and contains all constants from pi to cos(42^e). > > Somehow, it already does (i.e. internally it keeps track of their symbollic nature): {{{ sage: b=RLF(cos(42^e)) sage: b 0.9578837974? sage: b.eval(SR) cos(42^e) }}} Maybe the issue is that there is no coercion between SR and RLF (there is conversion from SR to RLF, and the .eval() method that can take elements from RLF to SR, though). -- You received this message because you are subscribed to the Google Groups "sage-devel" group. To unsubscribe from this group and stop receiving emails from it, send an email to sage-devel+unsubscr...@googlegroups.com. To post to this group, send email to sage-devel@googlegroups.com. Visit this group at http://groups.google.com/group/sage-devel. For more options, visit https://groups.google.com/d/optout.
- [sage-devel] Re: Re: How to define a new ring class... Marc Mezzarobba
- Re: [sage-devel] Re: Re: How to define a new ri... Vincent Delecroix
- Re: [sage-devel] Re: Re: How to define a ne... Thierry
- Re: [sage-devel] Re: Re: How to define a ne... Vincent Delecroix
- Re: [sage-devel] Re: Re: How to define a ne... Thierry
- Re: [sage-devel] Re: Re: How to define a ne... Felix Salfelder
- Re: [sage-devel] Re: How to define a new ring class... Vincent Delecroix
- Re: [sage-devel] Re: How to define a new ring class... Volker Braun
- Re: [sage-devel] Re: How to define a new ring c... Vincent Delecroix
- Re: [sage-devel] Re: How to define a new ri... Thierry
- Re: [sage-devel] Re: How to define a new ri... mmarco
- Re: [sage-devel] Re: How to define a new ri... Vincent Delecroix
- Re: [sage-devel] Re: How to define a new ri... mmarco
- Re: [sage-devel] Re: How to define a new ri... Vincent Delecroix
- Re: [sage-devel] Re: How to define a new ri... mmarco
- Re: [sage-devel] Re: How to define a new ring c... Thierry
- Re: [sage-devel] Re: How to define a new ri... Volker Braun
- Re: [sage-devel] Re: How to define a new ring class ? Vincent Delecroix