You're right, thanks.
David

On Wed, Apr 29, 2015 at 6:11 AM, Jeroen Demeyer <[email protected]>
wrote:

> There is no problem with reducible polynomials, only with non-squarefree
> polynomials. The correct statement is:
>
> If your actual polynomial lies in the squarefree locus, it is possible to
> increase precision enough so that a ball around it lies entirely within the
> squarefree locus.  But if the actual polynomial is not squarefree, any ball
> will intersect the squarefree locus.
>
>
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