sage: B=PermutationGroup(['(1,2,4,5,3)','(2,3,1,4,5)']) sage: B == AlternatingGroup(5) True sage: B == AlternatingGroup(7) False
On 5/05/2009, at 6:47 PM, jimfar wrote: > I have generated a group using, > sage: B=PermutationGroup(['(1,2,4,5,3)','(2,3,1,4,5)']) > And I know I can generate a list of the elements and determine the > order, but how do I show that this is actually > sage: AlternatingGroup(5). > > Is there a command to verify that B=AlternatingGroup(5)? -- http://yomcat.geek.nz --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
