thank you very much
On May 4, 11:57 pm, Michael Welsh <yom...@yomcat.geek.nz> wrote:
> sage: B=PermutationGroup(['(1,2,4,5,3)','(2,3,1,4,5)'])
> sage: B == AlternatingGroup(5)
> True
> sage: B == AlternatingGroup(7)
> False
>
> On 5/05/2009, at 6:47 PM, jimfar wrote:
>
> > I have generated a group using,
> > sage: B=PermutationGroup(['(1,2,4,5,3)','(2,3,1,4,5)'])
> > And I know I can generate a list of the elements and determine the
> > order, but how do I show that this is actually
> > sage: AlternatingGroup(5).
>
> > Is there a command to verify that B=AlternatingGroup(5)?
>
> --http://yomcat.geek.nz
--~--~---------~--~----~------------~-------~--~----~
To post to this group, send email to sage-support@googlegroups.com
To unsubscribe from this group, send email to
sage-support-unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/sage-support
URLs: http://www.sagemath.org
-~----------~----~----~----~------~----~------~--~---
