I can find the order of the element, but I am looking to generate a
list of all of the 3 cycles in something like AlternatingGroup(5)
where the list will not go on for too long.

On May 14, 5:04 pm, David Joyner <wdjoy...@gmail.com> wrote:
> I must be missing something. Why can't you just check the order of the 
> element?
>
> On Thu, May 14, 2009 at 7:53 PM, jimfar <jamesfar...@mac.com> wrote:
>
> > I can generate a list from any given group, but how would I go about
> > generating a list of just 3 or 5 cycles?
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