Thanks, I was confusing myself with the definition of the order of an element with order of the cycle.
On May 14, 6:52 pm, David Joyner <wdjoy...@gmail.com> wrote: > Why doesn't the obvious 1-liner > > [x for x in AlternatingGroup(5) if x.order()==3] > > work? Again, am I missing something? > > On Thu, May 14, 2009 at 8:57 PM, jimfar <jamesfar...@mac.com> wrote: > > > I can find the order of the element, but I am looking to generate a > > list of all of the 3 cycles in something like AlternatingGroup(5) > > where the list will not go on for too long. > > > On May 14, 5:04 pm, David Joyner <wdjoy...@gmail.com> wrote: > >> I must be missing something. Why can't you just check the order of the > >> element? > > >> On Thu, May 14, 2009 at 7:53 PM, jimfar <jamesfar...@mac.com> wrote: > > >> > I can generate a list from any given group, but how would I go about > >> > generating a list of just 3 or 5 cycles? --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
