let us do, f=function('f',x) expr=f(x) expr.operands()
the out put is, [x] Is it a bug?, I expect [f(x)]. using, f=function('f',x) expr=2*f(x) expr.operands() correctly gives, [f(x),2] -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org To unsubscribe, reply using "remove me" as the subject.