On Sat, Apr 3, 2010 at 11:15 AM, pallab <[email protected]> wrote: > let us do, > > f=function('f',x) > expr=f(x) > expr.operands() > > the out put is, > > [x] > > Is it a bug?,
No, it's not a bug since the operator is the function f: sage: f.operator() f --Mike -- To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org To unsubscribe, reply using "remove me" as the subject.
