Hi,
ok I have better understood what you have just said.
But mathematically what is the meaning of this:
%f ([1, 1, - --------------, --------------],
4, 3 2 2
sqrt(3) %i - 1 sqrt(3) %i
+ 1 %i
[2, - --------------,
--------------], --)
2
2 2
(%i3)
that I have found by this commands on terminal:
maxima_console()
;;; Loading #P"/home/saverio/sage/local/lib/ecl/defsystem.fas"
;;; Loading #P"/home/saverio/sage/local/lib/ecl/cmp.fas"
;;; Loading #P"/home/saverio/sage/local/lib/ecl/sysfun.lsp"
Maxima 5.20.1 http://maxima.sourceforge.net
using Lisp ECL 10.2.1
Distributed under the GNU Public License. See the file COPYING.
Dedicated to the memory of William Schelter.
The function bug_report() provides bug reporting information.
(%i1) sum(((2*I)^n/(n^3+1)*(1/4)^n),n,0,oo)
(%i2) load(simplify_sum)
(%i2) simplify_sum(sum(((2*%i)^n/(n^3+1)*(1/4)^n),n,0,inf));
Incorrect syntax: SIMPLIFY_SUM is not an infix operator
Incorrect syntax: Too many )'s
Incorrect syntax: Premature termination of input at ;.
(%i2) simplify_sum(sum(((2*%i)^n/(n^3+1)*(1/4)^n),n,0,inf))
(%i2) ;
sqrt(3) %i + 1 sqrt(3) %i - 1
(%o2) %f ([1, 1, - --------------, --------------],
4, 3 2 2
sqrt(3) %i - 1 sqrt(3) %i
+ 1 %i
[2, - --------------,
--------------], --)
2
2 2
(%i3)
Then the result of the summation of ((2*I)^n/(n^3+1)*(1/4)^n) where n
go from 0 to infity is: what?
What is the meaning of %?
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