On Sep 15, 10:20 am, sps <[email protected]> wrote:
> Hi,
> ok I have better understood what you have just said.
>
> But mathematically what is the meaning of this:
>  %f    ([1, 1, - --------------, --------------],
>         4, 3                2               2
>                                            sqrt(3) %i - 1  sqrt(3) %i
> + 1   %i
>                                      [2, - --------------,
> --------------], --)
>                                                  2
> 2          2
> (%i3)
> that I have found by this commands on terminal:
>
> maxima_console()
> ;;; Loading #P"/home/saverio/sage/local/lib/ecl/defsystem.fas"
> ;;; Loading #P"/home/saverio/sage/local/lib/ecl/cmp.fas"
> ;;; Loading #P"/home/saverio/sage/local/lib/ecl/sysfun.lsp"
> Maxima 5.20.1http://maxima.sourceforge.net
> using Lisp ECL 10.2.1
> Distributed under the GNU Public License. See the file COPYING.
> Dedicated to the memory of William Schelter.
> The function bug_report() provides bug reporting information.
> (%i1) sum(((2*I)^n/(n^3+1)*(1/4)^n),n,0,oo)
>
> (%i2) load(simplify_sum)
> (%i2) simplify_sum(sum(((2*%i)^n/(n^3+1)*(1/4)^n),n,0,inf));
> Incorrect syntax: SIMPLIFY_SUM is not an infix operator
> Incorrect syntax: Too many )'s
> Incorrect syntax: Premature termination of input at ;.
> (%i2) simplify_sum(sum(((2*%i)^n/(n^3+1)*(1/4)^n),n,0,inf))
> (%i2) ;
>
>                       sqrt(3) %i + 1  sqrt(3) %i - 1
> (%o2) %f    ([1, 1, - --------------, --------------],
>         4, 3                2               2
>                                            sqrt(3) %i - 1  sqrt(3) %i
> + 1   %i
>                                      [2, - --------------,
> --------------], --)
>                                                  2
> 2          2
> (%i3)
>
> Then the result of the summation of ((2*I)^n/(n^3+1)*(1/4)^n) where n
> go from 0 to infity is: what?
> What is the meaning of %?

That is how Maxima represents some things - %e is e, %i is i, and %f
is (apparently) the hypergeometric function.  Read up on that and see
if that answers your questions.

- kcrisman

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