Hi,

Thanks for such quick responses!
Unfortunately, having the Tayor series approach out, don't think it's
really appropriate for my problem afterall, as what I esentially need
to do is find the coefficientsof p^0*y^0, p, y, p^2*y etc in the
formula
(0.030*0.248244^y)y+0.05721*(0.248244^y)p +0.08838*(0.248244^y)
and was hoping that there may be a simple way of evaluating 0.248244^y
as 0.248244^0 + 0.248244^1*y^1+ 0.248244^2*y^2...as this would have
subsequently allowed me to look up the coefficients in the next step
Yet, the correct application of the Taylor series, as you pointed out,
is 0.248244^y = 0.248244^0 + ln(0.248244)*0.248244y + .... and so I'm
still in need of guidance for where to go next!

Thinking back to finding the coefficients, relating to Andrzej's
advice, if we call the formula:
i(p,y) = (0.030*0.248244^y)y+0.05721*(0.248244^y)p
+0.08838*(0.248244^y)
By using the function
i(p,y).coefficients()
sage outputs these coefficients as
[[0.03*0.248244^y*y + 0.08838*0.248244^y, 0], [0.05721*0.248244^y, 1]]
With more basic two-variable problems, I have used the command similar
to Andrzej's:
i(p,y).polynimial(SR).coefficient([0,0]) which outputs the specific
coefficient for p^0*y^0, and we coud then maybe substitute y=0 into
the coefficient after it is pulled out
But as there are still powers of y involved with the coefficients at
the primary stage, the i(p,y).polynimial(SR).coefficient([0,0])
command gives an error message.

With ony the i(p,y).coefficients() command, I can see by inspection
that to find the coefficients of p^0*y^0, I need first pull out the
1st bracket, as above, and evaluate 0.248244^0 to find the coefficient
And similarly to find the coefficients of p^0*y^1, I need first pull
out the 1st bracket, as above, and evaluate 0.248244^1 to find the
coefficient

Are you aware if there is a way to do this in sage?

Thank you,
Julie

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