partially answering my own question: for the "lame but easy method",
one can do the following. Having a putative group H, try:
for x in [g for g in G.Centre().Elements() if g.Order() == 2]:
Q= G.FactorGroupNC( G.Subgroup([ x ]) ) # no idea why NC
if Q.IdGroup() == what you want
return True
... or something.
2013/1/14 Pierre <[email protected]>:
> Thanks, I thought about this, but I'm not sure how to pick central elements
> of order 2 in a group, or more precisely in a group that is given by
> gap("SmallGroup(n,i)"). I can try C= G.centre() and then get C.generators()
> but i'm not sure if I can assume anything about these generators (I doubt
> that they generate cyclic subgroups whose *direct* product is C).
>
> Am I missing something easy?
>
> Le lundi 14 janvier 2013 13:35:05 UTC+1, Volker Braun a écrit :
>>
>> Lame but easy method: Go though all groups with 2*G.Size() elements and
>> pick out the ones you want.
>
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Pierre
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