On Sunday, March 17, 2013 10:56:22 PM UTC-4, david kircos wrote:
>
> http://i50.tinypic.com/a4wok1.png
>
> A screenshot is above^
>
> This seems kinda odd to me.  Is there a way to consistently return the 
> unevaluated form of the integral?
>
Think of this in terms of composite functions.  You first ask for 
integral(x^2,x) (which is x^3/3) and then ask for show() of that. So it 
shows that.  Does that make sense?

As to your second question, Maxima (our backend for integrals) does allow 
this, but I don't think we enable this.  I suspect there is some workaround 
- my apologies that I don't have time to think of it now; unfortunately, 
the one that works for many operations (adding "hold=True" as a keyword) 
does not work for integration.  Someone else will hopefully remember.

- kcrisman

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