On 2014-06-06, kcrisman <[email protected]> wrote: > lim(1/n^2*integrate(sin((2*n+1)*x)/sinh(x),x,0,pi/2),n=infinity)
I couldn't make any progress with the integral (in Maxima). Computing the integral numerically with quad_qawo (same function should be in Sage somewhere) suggests that it's pi/2 as n increases without bound. So I'm guessing the limit is zero. If you need a proof, maybe you can show the integral is bounded, therefore the limit is zero. Sorry I can't be more helpful, Robert Dodier -- You received this message because you are subscribed to the Google Groups "sage-support" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sage-support. For more options, visit https://groups.google.com/d/optout.
