Mathematica provides an answer of -3*pi/2, but that answer is incorrect. I wanted to see if Sage could compute the correct solution
On Thursday, June 5, 2014 11:24:39 PM UTC-4, Robert Dodier wrote: > > On 2014-06-06, kcrisman <[email protected] <javascript:>> wrote: > > > lim(1/n^2*integrate(sin((2*n+1)*x)/sinh(x),x,0,pi/2),n=infinity) > > I couldn't make any progress with the integral (in Maxima). > Computing the integral numerically with quad_qawo (same function should > be in Sage somewhere) suggests that it's pi/2 as n increases without > bound. So I'm guessing the limit is zero. > > If you need a proof, maybe you can show the integral is bounded, > therefore the limit is zero. > > Sorry I can't be more helpful, > > Robert Dodier > > -- You received this message because you are subscribed to the Google Groups "sage-support" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sage-support. For more options, visit https://groups.google.com/d/optout.
