#11905: Remove _splitting_field() from elliptic curves
-------------------------------------+-------------------------------------
       Reporter:  jdemeyer           |        Owner:  cremona
           Type:  enhancement        |       Status:  new
       Priority:  major              |    Milestone:  sage-6.1
      Component:  elliptic curves    |   Resolution:
       Keywords:                     |    Merged in:
        Authors:  Jeroen Demeyer     |    Reviewers:
Report Upstream:  N/A                |  Work issues:
         Branch:                     |       Commit:
  u/jdemeyer/ticket/11905            |  810ceecec7f6d507c5392fe2f2d00af18778f473
   Dependencies:  #2217, #15626,     |     Stopgaps:
  #11271                             |
-------------------------------------+-------------------------------------

Comment (by cremona):

 Replying to [comment:20 jdemeyer]:
 > Replying to [comment:19 cremona]:
 > > I know that this is not yet marked as ready for review, but I did look
 at the code anyway.  One minor remark:  after adjoining all the
 x-coordinates of the p-division points, *either* you have the full
 division field already, i.e. you have all the y-coordinates, *or* you have
 none, i.e. you have none of the y-coordinates.  This could be used,
 possibly, to simplify that last part of the division field code.  But it
 is not clear to me that there is a quicker way of determining that final
 quadratic extension than picking any of the x-coordinates of a p-division
 point and solving for y.
 > Not that I don't believe you, but do you have a reference for this? At
 least I could add it as a comment in the code.

 Proof.   For all P in E[p] and all Galois autos sigma (of K-bar over K) we
 have sigma(P)=+/-P since x(sigma(P))=sigma(x(P))=x(P).  Let P1, P2 be a
 basis for E[p].  For each sigma we have sigma(P1)=+/-P1 and
 sigma(P2)=+/-P2 and the signs are the *same* otherwise sigma(P1+P2) could
 not equal either +(P1+P2) or -(P1+P2).  So the image of sigma in the mod p
 Galois representation is either the identity or minus the identity.  In
 the first case, sigma fixes all points in E[p], in the second case it
 negates all of them.  So if the Galois rep is not trivial, its image has
 order 2 and its kernel cuts out a quadratic extension, say L/K.  In the
 latter case the non-trivial element sigma of Gal(L/K) maps to -1 which
 means that sigma(P)=-P for *all* P in E[p].

 I don't know a reference!

--
Ticket URL: <http://trac.sagemath.org/ticket/11905#comment:21>
Sage <http://www.sagemath.org>
Sage: Creating a Viable Open Source Alternative to Magma, Maple, Mathematica, 
and MATLAB

-- 
You received this message because you are subscribed to the Google Groups 
"sage-trac" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to [email protected].
To post to this group, send email to [email protected].
Visit this group at http://groups.google.com/group/sage-trac.
For more options, visit https://groups.google.com/groups/opt_out.

Reply via email to