#16866: Radical difference families
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Reporter: vdelecroix | Owner:
Type: enhancement | Status: needs_info
Priority: major | Milestone: sage-6.4
Component: combinatorial | Resolution:
designs | Merged in:
Keywords: | Reviewers:
Authors: Vincent Delecroix | Work issues:
Report Upstream: N/A | Commit:
Branch: | 721af75ec2b2c6ca904f2feaf86e75e054cb089d
u/vdelecroix/16866 | Stopgaps:
Dependencies: #16863 |
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Comment (by vdelecroix):
Replying to [comment:20 ncohen]:
> Yo!
>
> > Nope, and I do not need to do so. I want that my set of differences
cover the whole H. Because all differences are a union of cosets of H^mt^,
you can quotient out by H^mt^ (i.e. reasoning in terms of the cosets
xH^mt^).
>
> Hmmmm... I spent the last hour in front of that code, and I still don't
understand how exactly it works.
Too bad. If you tell me where, I can be clearer in the comments.
> Besides, I wonder: do you think that it makes any difference in the
computations? If you want to compute a tiling with the sets A0, A1, ... it
will take the same time as doing it on A0 U A0', A1 U A1', ... where the
Ai' are copies of the Ai on a disjoint set.
What do you mean by "the same time". There is the same number of tiles in
the packing at the end but if you ignore the symmetries there are much
more possible translations.
> What do you think ?
That my code works and that it is good to have smaller instances of the
problem to solve.
Vincent
--
Ticket URL: <http://trac.sagemath.org/ticket/16866#comment:21>
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