#14801: Piecewise functions done right
-------------------------------------+-------------------------------------
Reporter: vbraun | Owner: burcin
Type: defect | Status: needs_work
Priority: major | Milestone: sage-6.4
Component: symbolics | Resolution:
Keywords: | Merged in:
Authors: Volker Braun, | Reviewers:
Ralf Stephan | Work issues:
Report Upstream: N/A | Commit:
Branch: public/piecewise | 80e8f85240fdb7904c1339d0438243abf1238f00
Dependencies: #14800, #14780, | Stopgaps:
#9556, #13125, #14802, #16397, |
#17759 |
-------------------------------------+-------------------------------------
Changes (by rws):
* dependencies: #14800, #14780, #9556, #13125, #14802, #16397 => #14800,
#14780, #9556, #13125, #14802, #16397, #17759
Comment:
Replying to [comment:27 jdemeyer]:
> The result should be `y^3` as in:
> {{{
> sage: f(x) = y^3
> sage: f(1)
> y^3
> }}}
OK, this works now with '''one''' variable, dependent on #17759 (please
review). I'm of the opinion this should work too:
{{{
sage: f(x,y) = piecewise([((0,2), y^3)])
sage: f(1,1)
TypeError: __call__() takes at most 5 arguments (6 given)
}}}
but I have no idea atm what changes are needed for this.
`piecewise([((0,2), y^3)], var=(x,y))` is certainly not supported now.
--
Ticket URL: <http://trac.sagemath.org/ticket/14801#comment:34>
Sage <http://www.sagemath.org>
Sage: Creating a Viable Open Source Alternative to Magma, Maple, Mathematica,
and MATLAB
--
You received this message because you are subscribed to the Google Groups
"sage-trac" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
To post to this group, send email to [email protected].
Visit this group at http://groups.google.com/group/sage-trac.
For more options, visit https://groups.google.com/d/optout.
