#12179: Binomial of integer (mod n) returns integer
-------------------------------------+-------------------------------------
Reporter: scotts | Owner: AlexGhitza
Type: defect | Status: needs_work
Priority: major | Milestone: sage-6.4
Component: basic arithmetic | Resolution:
Keywords: binomial | Merged in:
coefficient modulo sd35 | Reviewers: Colton Pauderis,
Authors: Sam Scott, Marco | Johan Bosman, Marco Streng
Streng | Work issues:
Report Upstream: N/A | Commit:
Branch: | Stopgaps:
Dependencies: |
-------------------------------------+-------------------------------------
Comment (by vdelecroix):
Replying to [comment:24 mstreng]:
> Replying to [comment:23 vdelecroix]:
> > sage: R = Integers(21)
> > sage: binomial(R(5), R(2))
> > 10
>
> This should be {{{TypeError}}}, because {{{binomial(x,y)}}} makes no
sense when y is an element of {{{R}}}. It only makes sense when y is an
integer. For example, binomial(5, 2) = 10, but binomial(5, 2+21) = 0.
>
> So of the two points in the ticket description, the work in #17852 fixes
the second one, but the first one is still open.
Right!
--
Ticket URL: <http://trac.sagemath.org/ticket/12179#comment:25>
Sage <http://www.sagemath.org>
Sage: Creating a Viable Open Source Alternative to Magma, Maple, Mathematica,
and MATLAB
--
You received this message because you are subscribed to the Google Groups
"sage-trac" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
To post to this group, send email to [email protected].
Visit this group at http://groups.google.com/group/sage-trac.
For more options, visit https://groups.google.com/d/optout.
