#10638: Plot vectors of expressions without using parametric
---------------------------+------------------------------------------------
Reporter: kcrisman | Owner: jason, was
Type: enhancement | Status: new
Priority: minor | Milestone:
Component: graphics | Keywords:
Author: | Upstream: N/A
Reviewer: | Merged:
Work_issues: |
---------------------------+------------------------------------------------
Old description:
> It turns out that
> {{{
> sage: w = vector([x^2,3,x^3])
> sage: plot(w,(x,0,1))
> ---------------------------------------------------------------------------
> NotImplementedError
> }}}
> I guess this makes sense, since it is parametric. But this seems
> reasonable to implement.
>
> Far worse is
> {{{
> from sage.structure.element import is_Vector
> if kwds.get('parametric',False) and is_Vector(funcs):
> funcs = tuple(funcs)
>
> if hasattr(funcs, 'plot'):
> G = funcs.plot(*args, **original_opts)
> # if we are using the generic plotting method
> else:
> }}}
> Which means that plotting a numeric vector apparently doesn't go through
> its custom `.plot()` method. ???
>
> Anyway, we should figure out how to change this so that the vector
> plotting in 2 and 3 D is uniform in style.
New description:
It turns out that
{{{
sage: w = vector([x^2,3,x^3])
sage: plot(w,(x,0,1))
---------------------------------------------------------------------------
NotImplementedError
}}}
I guess this makes sense, since it is parametric. But this seems
reasonable to implement.
--
Comment(by kcrisman):
Updating description and summary to reflect that the other issue needs to
be taken care of for #2100 to be finished.
--
Ticket URL: <http://trac.sagemath.org/sage_trac/ticket/10638#comment:2>
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