#10888: problem in evaluation dual isogeny
-------------------------------+--------------------------------------------
Reporter: wuthrich | Owner: cremona
Type: defect | Status: new
Priority: major | Milestone:
Component: elliptic curves | Keywords: isogenies,
Author: | Upstream: N/A
Reviewer: | Merged:
Work_issues: |
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Comment(by wuthrich):
The problem is very simply that evaluation in a polynomial with two
variables does not give back a constant, but a constant polynomial. Is
this a bug ?
{{{
sage: R.<x,y> = PolynomialRing(ZZ,2)
sage: f(x=2,y=0)
-2
sage: type(f(x=2,y=0))
<type
'sage.rings.polynomial.multi_polynomial_libsingular.MPolynomial_libsingular'>
}}}
It is certainly not consitent with this :
{{{
sage: R.<x> = PolynomialRing(ZZ)
sage: f= x^2+3
sage: type(f(x=2))
<type 'sage.rings.integer.Integer'>
}}}
--
Ticket URL: <http://trac.sagemath.org/sage_trac/ticket/10888#comment:1>
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