I made some more test for the 4 Ts penalty It looks like it occures once every 8 Ts (8 pixels?) and when you have multiple INs at multiples of 8Ts intervals with a minimum of 16 Ts ofcourse. only the first IN might get the penalty and the others won't because the first IN synched them(the same counts for OUT (n),A ). Example:
in a,(n) ;12/16 nop ;4 in a,(n);12 jr $+2 ;12 in a,(n);12 So if you write youre code carefully you could fill the penalty time with more useful instructions Edwin
