Le 08/11/2011 11:47, Romain Beauxis a écrit :
> 2011/11/7 Martin Hamant<[email protected]>:
>>
>> Le 07/11/2011 11:57, Romain Beauxis a écrit :
>>> I am wondering something tough: could you benefit from another design
>>> of your solution?
>> Why not !
>>> Sources IDs are unique and retrievable using source.id. Thus, why not
>>> using a separate list of source's metadata_url values, indexed by
>>> source ID? Something like:
>> Do you speak about the source ID I specify at output creation ?
>>
>> output = out(id="#{stream_id}".....)
>>
>> Because if yes - as this is the same stream_id I use in robinet - the only
>> thing I would need to pass on telnet to call update_url correctly is
>>
>> update_url<stream_id>|<metadata_url>
> Correct! The only detail is that the id you pass may be rewritten if
> there is already another source registered in the system with the same
> ID. In this case, source.id(output) should return the updated ID. Of
> course, if you did the right thing, this should not happen :-)
Yes... I see what you're talking about ;)
>
>>> # The list
>>> sources_metadata_urls = ref []
>>>
>>> # Update it
>>> def update_url(source, url) =
>>> id = source.id(s)
>>> elem = (id, url)
>> def update_url(uri) =
>>
>> param = string.split(separator="\|",uri)
>> id = list.nth(param,0)
>> url = list.nth(param,1)
>>
>> elem = (id, url)
>> (...)
>>
>> Would be right ?
>>
> It is my call to list.fold which is incorrect. It should be:
> sources_metadata_urls := list.fold(f, [], !sources_metadata_urls)
Yes, this is what I guessed at the first place, but trying this showed
that this is not all :)
I've make it work with the following code:
def update_url(uri) =
param = string.split(separator="\|",uri)
id = list.nth(param,0)
url = list.nth(param,1)
elem = (id, url)
# Directly append if not already present
if not list.mem_assoc(id, !sources_metadata_urls) then
sources_metadata_urls := list.append([elem], !sources_metadata_urls)
else
# This is more painful..
def f(x, cur) =
test_id = fst(cur) # instead of fst(x)
# Update if given element matches
if test_id == id then
list.append([elem], x) # instead of list.append([elem], cur)
else
# Otherwise, put it back
list.append([cur], x) # instead of list.append([x], cur)
end
end
sources_metadata_urls := list.fold(f, [], !sources_metadata_urls) #
added the missing [] original value for x
end
print(sources_metadata_urls) # debug
"Done!" # this is required
end
It works like expected, I'm going forward to the next step !
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