Le 21/11/2011 16:41, David Baelde a écrit :
> On Mon, Nov 21, 2011 at 4:01 PM, Martin Hamant<[email protected]> wrote:
>> Tell me if ... this is viable... or if there is a "clearer" way to write
>> that !?
> No comment, it looks very good to me. Congratulations!
>
> David
WoOt !
I begin to understand the philosophy :D
Another quick question:
In the following piece of code of create_playlist()
dyn_sources :=
list.append( [(uri,{ source.shutdown(s0) ;
source.shutdown(output) ; delay := (-1.) })],
!dyn_sources )
I want to remove the pair (id, path) from sources_metadata_paths list.
So I have tried the following with no success... (the pair is not
removed from the list)
dyn_sources :=
list.append( [(uri,{ source.shutdown(s0) ;
source.shutdown(output) ; print("removing for source id:") ;
print(source.id(output)) ; sources_metadata_paths :=
list.remove_assoc(source.id(output), !sources_metadata_paths) ;
print(sources_metadata_paths) ; delay := (-1.) })],
!dyn_sources )
Thanks !
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