just try it? In intellij, if I type `var wakeLock: WakeLock = null` and it prompts to import `android.os.PowerManager.WakeLock` then the import statement says "Cannot resolve symbol WakeLock`. If I clean and compile from sbt console, I get "value WakeLock is not a member of object android.os.PowerManager".
Also, WakefulBroadcastReceiver is an abstract class, so no, I can't simply call the static methods on it. On Wed, Dec 3, 2014 at 10:24 AM, Samuel Tardieu <s...@rfc1149.net> wrote: > > > 2014-12-03 17:09 GMT+01:00 Daniel Skinner <dan...@dasa.cc>: > >> I'm still learning a few things about scala but I'm wondering if anyone >> has insight on accessing java statics from scala in relation to the Android >> API. This rarely comes up but here's two examples. >> >> From https://developer.android.com/training/scheduling/wakelock.html >> >> The support library has a WakefulBroadcastReceiver that contains two >> static methods. If i create a scala class that extends this, I can't access >> the static methods for starting a wakeful service and finishing it. >> > > What do you mean you “can’t access” them? You can imagine Java static > methods as being roughly methods in a class companion object. You don’t > inherit them, the way you wouldn’t inherit methods from a companion object > as they don’t belong to the corresponding class, and they don’t operate on > a particular instance. You need to access those methods by calling > WakefulBroadcastReceiver.startWakefulService(…). In Java, being able to > call them as if they were methods of your class is merely a convenience, > they can’t access any of your non-static methods or fields anyway. > > > . > >> >> Likewise, >> http://developer.android.com/reference/android/os/PowerManager.WakeLock.html >> I can't declare a WakeLock type with something like `val wakeLock: WakeLock >> = null`. >> > > Again, what do you mean by “I can’t declare a WakeLock”? What happens if > you do? I don’t see any reason you couldn’t declare one and assign it the > null value (although an Option[WakeLock] would probably be best here). > > > > >> >> I have an intent service and worked around this with the following that I >> access in onCreate and onDestroy (letting the type be inferred) >> >> lazy val (wakeLock, wifiLock) = { >> val pm = >> getSystemService(Context.POWER_SERVICE).asInstanceOf[PowerManager] >> val wakeLock = pm.newWakeLock(PowerManager.PARTIAL_WAKE_LOCK, >> "ClientWakeLock") >> wakeLock.acquire() >> val wm = >> getSystemService(Context.WIFI_SERVICE).asInstanceOf[WifiManager] >> val wifiLock = wm.createWifiLock(WifiManager.WIFI_MODE_FULL, >> "ClientWifiLock") >> wifiLock.acquire() >> (wakeLock, wifiLock) >> } >> >> but I'm wondering if there's some other way so that I can declare the >> type. >> > > What is wrong with the type (WakeLock, WifiLock)? > > Sam > > > -- > You received this message because you are subscribed to the Google Groups > "scala-on-android" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to scala-on-android+unsubscr...@googlegroups.com. > For more options, visit https://groups.google.com/d/optout. > -- You received this message because you are subscribed to the Google Groups "scala-on-android" group. To unsubscribe from this group and stop receiving emails from it, send an email to scala-on-android+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
