iirc val lock: PowerManager#WakeLock
On Wed Dec 03 2014 at 8:38:54 AM Daniel Skinner <dan...@dasa.cc> wrote: > just try it? In intellij, if I type `var wakeLock: WakeLock = null` and it > prompts to import `android.os.PowerManager.WakeLock` then the import > statement says "Cannot resolve symbol WakeLock`. If I clean and compile > from sbt console, I get "value WakeLock is not a member of object > android.os.PowerManager". > > Also, WakefulBroadcastReceiver is an abstract class, so no, I can't simply > call the static methods on it. > > On Wed, Dec 3, 2014 at 10:24 AM, Samuel Tardieu <s...@rfc1149.net> wrote: > >> >> >> 2014-12-03 17:09 GMT+01:00 Daniel Skinner <dan...@dasa.cc>: >> >>> I'm still learning a few things about scala but I'm wondering if anyone >>> has insight on accessing java statics from scala in relation to the Android >>> API. This rarely comes up but here's two examples. >>> >>> From https://developer.android.com/training/scheduling/wakelock.html >>> >>> The support library has a WakefulBroadcastReceiver that contains two >>> static methods. If i create a scala class that extends this, I can't access >>> the static methods for starting a wakeful service and finishing it. >>> >> >> What do you mean you “can’t access” them? You can imagine Java static >> methods as being roughly methods in a class companion object. You don’t >> inherit them, the way you wouldn’t inherit methods from a companion object >> as they don’t belong to the corresponding class, and they don’t operate on >> a particular instance. You need to access those methods by calling >> WakefulBroadcastReceiver.startWakefulService(…). In Java, being able to >> call them as if they were methods of your class is merely a convenience, >> they can’t access any of your non-static methods or fields anyway. >> >> >> . >> >>> >>> Likewise, >>> http://developer.android.com/reference/android/os/PowerManager.WakeLock.html >>> I can't declare a WakeLock type with something like `val wakeLock: WakeLock >>> = null`. >>> >> >> Again, what do you mean by “I can’t declare a WakeLock”? What happens if >> you do? I don’t see any reason you couldn’t declare one and assign it the >> null value (although an Option[WakeLock] would probably be best here). >> >> >> >> >>> >>> I have an intent service and worked around this with the following that >>> I access in onCreate and onDestroy (letting the type be inferred) >>> >>> lazy val (wakeLock, wifiLock) = { >>> val pm = >>> getSystemService(Context.POWER_SERVICE).asInstanceOf[PowerManager] >>> val wakeLock = pm.newWakeLock(PowerManager.PARTIAL_WAKE_LOCK, >>> "ClientWakeLock") >>> wakeLock.acquire() >>> val wm = >>> getSystemService(Context.WIFI_SERVICE).asInstanceOf[WifiManager] >>> val wifiLock = wm.createWifiLock(WifiManager.WIFI_MODE_FULL, >>> "ClientWifiLock") >>> wifiLock.acquire() >>> (wakeLock, wifiLock) >>> } >>> >>> but I'm wondering if there's some other way so that I can declare the >>> type. >>> >> >> What is wrong with the type (WakeLock, WifiLock)? >> >> Sam >> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "scala-on-android" group. >> To unsubscribe from this group and stop receiving emails from it, send an >> email to scala-on-android+unsubscr...@googlegroups.com. >> For more options, visit https://groups.google.com/d/optout. >> > > -- > You received this message because you are subscribed to the Google Groups > "scala-on-android" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to scala-on-android+unsubscr...@googlegroups.com. > For more options, visit https://groups.google.com/d/optout. > -- You received this message because you are subscribed to the Google Groups "scala-on-android" group. To unsubscribe from this group and stop receiving emails from it, send an email to scala-on-android+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
