On Tue, Dec 06, 2011 at 09:04:22AM +0100, Alexandre Gramfort wrote:
> > This actually gets at something I've been meaning to fiddle with and report 
> > but haven't had time: I'm not sure I completely trust the coordinate 
> > descent implementation in scikit-learn, because it seems to give me bogus 
> > answers a lot (i.e., the optimality conditions necessary for it to be an 
> > actual solution are not even approximately satisfied). Are you guys using 
> > something weird for the termination condition?
> 
> can you give us a sample X and y that shows the pb?
> 
> it should ultimately use the duality gap to stop the iterations but
> there might be a corner case …

In [34]: rng = np.random.RandomState(0)

In [35]: dictionary = rng.normal(size=(100, 500)) / 1000; dictionary /=
np.sqrt((dictionary ** 2).sum(axis=0))

In [36]: signal = rng.normal(size=100) / 1000

In [37]: from sklearn.linear_model import Lasso

In [38]: lasso = Lasso(alpha=0.0001, max_iter=1e6, fit_intercept=False,
tol=1e-8)

In [39]: lasso.fit(dictionary, signal)
Out[39]: 
Lasso(alpha=0.0001, copy_X=True, fit_intercept=False, max_iter=1000000.0,
   normalize=False, precompute='auto', tol=1e-08)

In [40]: max(abs(lasso.coef_))
Out[40]: 0.0

In [41]: from pylearn2.optimization.feature_sign import feature_sign_search

In [42]: coef = feature_sign_search(dictionary, signal, 0.0001)

In [43]: max(abs(coef))
Out[43]: 0.0027295761244725018

And I'm pretty sure the latter result is the right one, since

In [45]: def gradient(coefs):
   ....:     gram = np.dot(dictionary.T, dictionary)
   ....:     corr = np.dot(dictionary.T, signal)
   ....:     return - 2 * corr + 2 * np.dot(gram, coefs) + 0.0001 *
np.sign(coefs)
   ....: 


and

In [51]: max(abs(gradient(coef)[coef == 0]))
Out[51]: 9.9849794040467979e-05

In [52]: max(abs(gradient(lasso.coef_)))
Out[52]: 0.0065556004140218012

meaning that whatever that maximum gradient coefficient is should have been
activated, since the gradient from the linear portion should override the
sparsity penalty.

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