regarding the scaling by n_samples using estimators I am convinced the right
thing to do cf. my current PR to do this also on SVM models

regarding the convergence pb and potential error, can you put a gist on github
to make the pb more easily reproducible.

Alex

On Tue, Dec 6, 2011 at 9:17 PM, Ian Goodfellow <[email protected]> wrote:
> ok, decreasing alpha by a factor of n_samples (5000 in my case) makes
> sparse_encode behave much more reasonably.
>
> However I still have two bugs to report:
>
> 1. The default algorithm returns this error:
>
> Traceback (most recent call last):
>  File "s3c_sparsity_scale_plot.py", line 86, in <module>
>    HS = sparse_encode( model.W.get_value(), X.T, alpha = 1./5000.).T
>  File 
> "/u/goodfeli/python_modules/lib/python2.7/site-packages/scikit_learn-0.9-py2.7-linux-x86_64.egg/sklearn/decomposition/dict_learning.py",
> line 117, in sparse_encode
>    method='lasso')
>  File 
> "/u/goodfeli/python_modules/lib/python2.7/site-packages/scikit_learn-0.9-py2.7-linux-x86_64.egg/sklearn/linear_model/least_angle.py",
> line 249, in lars_path
>    arrayfuncs.cholesky_delete(L[:n_active, :n_active], idx)
>  File "arrayfuncs.pyx", line 104, in
> sklearn.utils.arrayfuncs.cholesky_delete
> (sklearn/utils/arrayfuncs.c:1516)
> TypeError: only length-1 arrays can be converted to Python scalars
>
>
> 2. The lasso_lars algorithm tells me I am not using enough iterations,
> but as far as I can tell the sparse_encode interface does not expose
> any way for me to increase the number of iterations that cd uses.
>
> /u/goodfeli/python_modules/lib/python2.7/site-packages/scikit_learn-0.9-py2.7-linux-x86_64.egg/sklearn/linear_model/coordinate_descent.py:173:
> UserWarning: Objective did not converge, you might want to increase
> the number of iterations
>  warnings.warn('Objective did not converge, you might want'
>
>
>
>
> On Tue, Dec 6, 2011 at 2:43 PM, Olivier Grisel <[email protected]> 
> wrote:
>> 2011/12/6 David Warde-Farley <[email protected]>:
>>> On Tue, Dec 06, 2011 at 09:04:22AM +0100, Alexandre Gramfort wrote:
>>>> > This actually gets at something I've been meaning to fiddle with and 
>>>> > report but haven't had time: I'm not sure I completely trust the 
>>>> > coordinate descent implementation in scikit-learn, because it seems to 
>>>> > give me bogus answers a lot (i.e., the optimality conditions necessary 
>>>> > for it to be an actual solution are not even approximately satisfied). 
>>>> > Are you guys using something weird for the termination condition?
>>>>
>>>> can you give us a sample X and y that shows the pb?
>>>>
>>>> it should ultimately use the duality gap to stop the iterations but
>>>> there might be a corner case …
>>>
>>> In [34]: rng = np.random.RandomState(0)
>>>
>>> In [35]: dictionary = rng.normal(size=(100, 500)) / 1000; dictionary /=
>>> np.sqrt((dictionary ** 2).sum(axis=0))
>>>
>>> In [36]: signal = rng.normal(size=100) / 1000
>>>
>>> In [37]: from sklearn.linear_model import Lasso
>>>
>>> In [38]: lasso = Lasso(alpha=0.0001, max_iter=1e6, fit_intercept=False,
>>> tol=1e-8)
>>>
>>> In [39]: lasso.fit(dictionary, signal)
>>> Out[39]:
>>> Lasso(alpha=0.0001, copy_X=True, fit_intercept=False, max_iter=1000000.0,
>>>   normalize=False, precompute='auto', tol=1e-08)
>>>
>>> In [40]: max(abs(lasso.coef_))
>>> Out[40]: 0.0
>>>
>>> In [41]: from pylearn2.optimization.feature_sign import feature_sign_search
>>>
>>> In [42]: coef = feature_sign_search(dictionary, signal, 0.0001)
>>>
>>> In [43]: max(abs(coef))
>>> Out[43]: 0.0027295761244725018
>>>
>>> And I'm pretty sure the latter result is the right one, since
>>>
>>> In [45]: def gradient(coefs):
>>>   ....:     gram = np.dot(dictionary.T, dictionary)
>>>   ....:     corr = np.dot(dictionary.T, signal)
>>>   ....:     return - 2 * corr + 2 * np.dot(gram, coefs) + 0.0001 *
>>> np.sign(coefs)
>>>   ....:
>>
>> Actually, alpha in scikit-learn is multiplied by n_samples. I agree
>> this is misleading and not documented in the docstring.
>>
>>>>> lasso = Lasso(alpha=0.0001 / dictionary.shape[0], max_iter=1e6, 
>>>>> fit_intercept=False, tol=1e-8).fit(dictionary, signal)
>>>>> max(abs(lasso.coef_))
>> 0.0027627270397484554
>>>>> max(abs(gradient(lasso.coef_)))
>> 0.00019687294269977963
>>
>> --
>> Olivier
>> http://twitter.com/ogrisel - http://github.com/ogrisel
>>
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