Re: [PHP] Curl output

2009-10-02 Thread kranthi
using the base tag is a solution to your problem if the links are relative..
http://www.w3schools.com/TAGS/tag_base.asp
but I am not sure if base tag works outside html/html

try... base href=URL/base before curl_init()
where URL is parsed using PHP's parse_url() function on http://example.com

in either case if there are any external js/css files cURL wont fetch
external files(and if they are internal/inline your browser should
display them already).. your browser will have to fetch them for you,
net console of firebug will be helpful in that case.

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Re: [PHP] Curl output

2009-10-02 Thread Ashley Sheridan
On Fri, 2009-10-02 at 12:51 +0530, kranthi wrote:
 using the base tag is a solution to your problem if the links are relative..
 http://www.w3schools.com/TAGS/tag_base.asp
 but I am not sure if base tag works outside html/html
 
 try... base href=URL/base before curl_init()
 where URL is parsed using PHP's parse_url() function on http://example.com
 
 in either case if there are any external js/css files cURL wont fetch
 external files(and if they are internal/inline your browser should
 display them already).. your browser will have to fetch them for you,
 net console of firebug will be helpful in that case.
 

Some browser security settings may not allow you to run Javascript code
that exists on another server though. The base tag can be used to
reference the external CSS and Javascript, but watch out for security
settings on client agents.

Thanks,
Ash
http://www.ashleysheridan.co.uk




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Re: [PHP] Curl output

2009-10-02 Thread kranthi
 Some browser security settings may not allow you to run Javascript code
 that exists on another server though
not many users use those kind of browsers, because if they do most of
the websites which use CDNs will not work.

Firstly, it is not a good idea to fetch an entire web page and snow it
to an user. (use iframes if this is a must)
Secondly, this idea may not be feasible if the web page in question
uses AJAX, because none of the browsers allow cross domain AJAX
requests

As a side note, use str_replace(head, headbase/base,
$text) if base tag doesnot work

On 02/10/2009, Ashley Sheridan a...@ashleysheridan.co.uk wrote:
 On Fri, 2009-10-02 at 12:51 +0530, kranthi wrote:
 using the base tag is a solution to your problem if the links are
 relative..
 http://www.w3schools.com/TAGS/tag_base.asp
 but I am not sure if base tag works outside html/html

 try... base href=URL/base before curl_init()
 where URL is parsed using PHP's parse_url() function on http://example.com

 in either case if there are any external js/css files cURL wont fetch
 external files(and if they are internal/inline your browser should
 display them already).. your browser will have to fetch them for you,
 net console of firebug will be helpful in that case.


 Some browser security settings may not allow you to run Javascript code
 that exists on another server though. The base tag can be used to
 reference the external CSS and Javascript, but watch out for security
 settings on client agents.

 Thanks,
 Ash
 http://www.ashleysheridan.co.uk






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Re: [PHP] Curl output

2009-10-02 Thread Ashley Sheridan
On Fri, 2009-10-02 at 15:59 +0530, kranthi wrote:
 not many users use those kind of browsers, because if they do most of
 the websites which use CDNs will not work.

I've read that the upcoming Firefox 4 may have some features built in
for this sort of thing, and there are plugins out there for most
browsers that can do this as an added layer of security.

On this front though, has anyone else read about Microsofts Gazelle
browser/os? I'm not trying to plug it here or anything (I'm an anti
Windows person myself!) but the concept looks interesting. It goes
further than Chrome where each tab has it's own process by giving each
domain specific object its own process/sandbox.

Thanks,
Ash
http://www.ashleysheridan.co.uk




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Re: [PHP] Curl output

2009-10-02 Thread kranthi
 I've read that the upcoming Firefox 4 may have some features built in
 for this sort of thing, and there are plugins out there for most
 browsers that can do this as an added layer of security.
Sorry but I could not understand what you meant by this

coming back to original problem... you should keep in mind that if
base tag is used, the links (a href=...) in that page will become
absolute links instead of relative links

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Re: [PHP] Curl output

2009-10-02 Thread Ashley Sheridan
On Fri, 2009-10-02 at 18:07 +0530, kranthi wrote:
  I've read that the upcoming Firefox 4 may have some features built in
  for this sort of thing, and there are plugins out there for most
  browsers that can do this as an added layer of security.
 Sorry but I could not understand what you meant by this
 
 coming back to original problem... you should keep in mind that if
 base tag is used, the links (a href=...) in that page will become
 absolute links instead of relative links
 

this is this:

Some browser security settings may not allow you to run Javascript code
that exists on another server though

Also, you won't have to worry about the links, unless you wanted the
links that were relative to the remote site to be relative to your own.
This would only work out in such a way if you'd scraped their whole site
for content, which would beg the question, why would someone honestly
need to scrape an entire site?

Thanks,
Ash
http://www.ashleysheridan.co.uk




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[PHP] Curl output

2009-10-01 Thread gbhumphrey

Hi, I am doing a basical curl call and can get the webpage I want. However
when it prints to the screen, it only prints the text, not css or any
javascript calls that run on page load.
Is there a way to make it do that?

thanks
using a basic curl call
$curl_handle=curl_init();
curl_setopt($curl_handle,CURLOPT_URL,'http://example.com');
curl_setopt($ch, CURLOPT_RETURNTRANSFER,0); // return into a variable
curl_exec($curl_handle);





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Re: [PHP] Curl output

2009-10-01 Thread Paul M Foster
On Thu, Oct 01, 2009 at 04:37:14PM -0700, gbhumphrey wrote:

 
 Hi, I am doing a basical curl call and can get the webpage I want. However
 when it prints to the screen, it only prints the text, not css or any
 javascript calls that run on page load.
 Is there a way to make it do that?
 
 thanks
 using a basic curl call
 $curl_handle=curl_init();
 curl_setopt($curl_handle,CURLOPT_URL,'http://example.com');
 curl_setopt($ch, CURLOPT_RETURNTRANSFER,0); // return into a variable
 curl_exec($curl_handle);

I don't know about the javascript, but if the CSS is an external file,
then it wouldn't get dragged along with the original file, and thus
wouldn't be there to style anything on the HTML page. Just a guess.

Paul

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Re: [PHP] Curl output

2009-10-01 Thread Jim Lucas

gbhumphrey wrote:

Hi, I am doing a basical curl call and can get the webpage I want. However
when it prints to the screen, it only prints the text, not css or any
javascript calls that run on page load.
Is there a way to make it do that?

thanks
using a basic curl call
$curl_handle=curl_init();
curl_setopt($curl_handle,CURLOPT_URL,'http://example.com');
curl_setopt($ch, CURLOPT_RETURNTRANSFER,0); // return into a variable
curl_exec($curl_handle);







Along the lines of what Paul has already alluded to, you will probably find upon further examination 
of the html source that the linked files (js, css, etc...) are probably using relative paths, not 
absolute paths including the domain name.


To fix this, you would have to do a little source code rewriting to add the full domain name and 
directory path information to the linked in url structure.


I know if you do this with wget (cli app) that you can have it re-write the domain + path url 
references.  But, I'm not sure if cURL has an option for that.  You might RTM on the cURL options 
page to find out.


http://php.net/curl


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   Some men are born to greatness, some achieve greatness,
   and some have greatness thrust upon them.

Twelfth Night, Act II, Scene V
by William Shakespeare

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[PHP] Curl output to an array -- HELP!!

2002-03-19 Thread Keith Posehn

Ok, lets say I have some code here:

$result = array();

$ch = curl_init (https://www.myverificationplace.com/verify.asp;);

curl_setopt ($ch, CURLOPT_POST, 1);
curl_setopt ($ch, CURLOPT_POSTFIELDS, $args);
curl_setopt ($ch, CURLOPT_TIMEOUT, 120); // Set the timeout, in seconds.
curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1);
$result = curl_exec ($ch);

curl_close ($ch);

Now that we see that, how can I make it so that the output from curl, which
is in the variable $result, will be an array, for each line of output?

Some of the line of output looks like this:

ssl_result_message=APPROVED
ssl_txn_id=----
ssl_approval_code=00

I need each of the lines to be turned into a variable. Any ideas as to how I
might go about this?

Thanks,

Keith Posehn





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[PHP] Curl output to an array -- HELP!! -- Appended

2002-03-19 Thread Keith Posehn

This is an revision of my previous message:

Ok, lets say I have some code here:

$result = array();

$ch = curl_init (https://www.myverificationplace.com/verify.asp;);

curl_setopt ($ch, CURLOPT_POST, 1);
curl_setopt ($ch, CURLOPT_POSTFIELDS, $args);
curl_setopt ($ch, CURLOPT_TIMEOUT, 120); // Set the timeout, in seconds.
curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1);
$result = curl_exec ($ch);

curl_close ($ch);

Now that we see that, how can I make it so that the output from curl, which
is in the variable $result, will be an array, for each line of output?

Some of the line of output looks like this:

ssl_result_message=APPROVED
ssl_txn_id=----
ssl_approval_code=00

I need each of the lines to be turned into a variable.

Example:

name the variable 'ssl_result_message', the value being 'APPROVED'

Any ideas as to how I might go about this?

Thanks,

Keith Posehn




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RE: [PHP] Curl output to an array -- HELP!! -- Appended

2002-03-19 Thread Martin Towell

(this code not tested)

?
$res_arr = explode(\n, $result);
$res_num = count($res_arr);
for ($i = 0; $i  $res_num; $i++)
{
  list($k, $v) = explode(=, $res_arr[$i]);
  $$k = $v;
}
?

this isn't going to work properly if the value part has an = in it - in
that case, change the explode(=, ...) line to use strtok() or
strpos()/substr()

HTH
Martin


-Original Message-
From: Keith Posehn [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 20, 2002 9:22 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Curl output to an array -- HELP!! -- Appended


This is an revision of my previous message:

Ok, lets say I have some code here:

$result = array();

$ch = curl_init (https://www.myverificationplace.com/verify.asp;);

curl_setopt ($ch, CURLOPT_POST, 1);
curl_setopt ($ch, CURLOPT_POSTFIELDS, $args);
curl_setopt ($ch, CURLOPT_TIMEOUT, 120); // Set the timeout, in seconds.
curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1);
$result = curl_exec ($ch);

curl_close ($ch);

Now that we see that, how can I make it so that the output from curl, which
is in the variable $result, will be an array, for each line of output?

Some of the line of output looks like this:

ssl_result_message=APPROVED
ssl_txn_id=----
ssl_approval_code=00

I need each of the lines to be turned into a variable.

Example:

name the variable 'ssl_result_message', the value being 'APPROVED'

Any ideas as to how I might go about this?

Thanks,

Keith Posehn




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RE: [PHP] Curl output to an array -- HELP!! -- Appended

2002-03-19 Thread mnc

On Wed, 20 Mar 2002, Martin Towell wrote:
 (this code not tested)
 
 ?
 $res_arr = explode(\n, $result);
 $res_num = count($res_arr);
 for ($i = 0; $i  $res_num; $i++)
 {
   list($k, $v) = explode(=, $res_arr[$i]);
   $$k = $v;
 }
 ?
 
 this isn't going to work properly if the value part has an = in it - in
 that case, change the explode(=, ...) line to use strtok() or
 strpos()/substr()

Explode takes an optional third argument, which limits the amount of
shrapnel produced. So just change that line to:

   list($k, $v) = explode(=, $res_arr[$i], 2);

and you're the Egyptian god of the underworld.

miguel


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