I think 'm[^/]*$' will match (parse) all end-parts that begin with 'm'.
I think '.*/m[^/]*$' will match (find) all full-paths that have an end-part
that begins with 'm' (or either of: 'm' or 'M' if 'i' flag is used).
I addressed parsing, not finding.
In javascript,
regExp=/.*\/m[^\/]*$/i;
would r
Le Lun 25 février 2013 2:23, David Christensen a écrit :
> On 02/24/13 16:48, Mark Filipak wrote:
>
>> Okay, here's my plan:
>> Linux - Mainly for WWW browsing & email.
>> Windows XP - For engineering applications & games - no networking at
>> all. Either multiboot, or VMware player with Linux host
On 02/24/13 16:48, Mark Filipak wrote:
Okay, here's my plan:
Linux - Mainly for WWW browsing & email.
Windows XP - For engineering applications & games - no networking at all.
Either multiboot, or VMware player with Linux host/WinXP client.
Comments? Advice? KISS.
My first step at multiboot was
a small correction of mine. i wanted to match not only last part but beggining
of last part . so your solution is ok and thanks. Based on it with a small
addition i can match the beggining of the last part of full path.
So:
'm[^\/]*$' (why \ needs quoting? , i think is not special character in
> For end of the fullpath, search for '[^\/]*$'
> For end of the fullpath that begins with 'm', search for 'm[^\/]*$'
>
'm[^\/]*$' (why \ needs quoting? , i think is not special character in perl
reg exprs)
'm[^/]*$' it will also match /bla/mbla/bla .
But based on your hint i think solution i
Thanks for the encouragement, Hugo, but I'm not real keen on freeware. Open
source is great, but free generally means not good and not supported - and a
user forum is not support. My experience has been with Firefox and Thunderbird.
Okay, here's my plan:
Linux - Mainly for WWW browsing & email.
Mark Filipak wrote:
For end of the fullpath, search for '[^\/]*$'
For end of the fullpath that begins with 'm', search for 'm[^\/]*$'
Caveats: I don't know perl & I don't use apt-file & I don't use linux.
(I lurk the Debian list because I'm considering trying Debian.) My
knowledge is javascrip
For end of the fullpath, search for '[^\/]*$'
For end of the fullpath that begins with 'm', search for 'm[^\/]*$'
Caveats: I don't know perl & I don't use apt-file & I don't use linux. (I lurk
the Debian list because I'm considering trying Debian.) My knowledge is javascript. The
patterns above
How can i match the last part of a full pathnname?
eg: apt-file -x search '^m.*' matches full paths with their topmost dirname
started with 'm' . How can i match the last part or the full path to start
with m for example ?
aprekates
http://librebytes.gr
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